y=(1/x^2)-1

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Solution for y=(1/x^2)-1 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

y = 1/(x^2)-1 // - 1/(x^2)-1

y-(1/(x^2))+1 = 0

y-x^-2+1 = 0

-1*x^-2 = -(y+1) // : -1

x^-2 = y+1

-2 < 0

1/(x^2) = y+1 // * x^2

1 = x^2*(y+1) // : y+1

1/(y+1) = x^2

x^2 = 1/(y+1) // ^ 1/2

abs(x) = 1/((y+1)^(1/2))

x = 1/((y+1)^(1/2)) or x = -(1/((y+1)^(1/2)))

x in { 1/((y+1)^(1/2)), -(1/((y+1)^(1/2))) }

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